Optics Questions with Solutions
Optics questions with solutions and explanations at the bottom of the page. These questions may be used to practice for the SAT physics test. The questions are about reflection, refraction, critical angle, lenses, reflectors, light rays propagating through different mediums, refractive index of materials, ..etc.
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Which of the following is true about light?
I) It is an electromagnetic wave
II) It does not propagates in vacuum
III) Its maximum speed is approximately 3×108 m/s
A) I only
B) I and II only
C) I and III only
D) III only
E) I, II and III
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The speed of light in a certain material is 50% of its speed in vacuum. What is the refractive index of this material?
A) 1.5
B) 0.5
C) 6.0
D) 2.0
E) 1.5×108
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What is the critical angle ic at the interface glass-cladding of an optical fiber whose core has a refractive index equal to 1.5 and cladding with a refractive index 1.45?
A) 15°
B) 105°
C) 86°
D) 83°
E) 75°
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Which of the following is true about light with a single wavelength?
I) It can be refracted
II) It cannot be dispersed
III) It can be reflected
A) I, II and III
B) I and II only
C) II and III only
D) I and III only
E) None
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A ray of light is incident in medium (1) where light has speed s1 onto the interface with medium (2) where light has speed s2. If s1 > s2, then at the interface
A) the ray will refract away from the normal to the interface
B) the ray will refract toward from the normal to the interface
C) the ray will follow a straight path from medium (1) to medium (2)
D) the angle of reflection is greater than the angle of incidence
E) the angle of reflection is not equal to the angle of incidence
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Parallel rays of light strikes a convex lens. Which of the following diagrams shows what happens to the rays when they strike the lens?
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An object of height 10 cm is placed 50 cm in front of a bi-convex lens with a focal length of 20 cm. Which of the following is true about the image?
I) The image is virtual
II) The image is situated on the opposite side as the object
III) The image is inverted
A) I only
B) I and II only
C) II and III only
D) II only
E) III only
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An object of height 5 cm is placed 25 cm in front of a bi-convex lens with a focal length of 10 cm. What is the height of the image?
A) 2.5 cm
B) 12.5 cm
C) 6.8 cm
D) 3.4 cm
E) 7.4 cm
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An optical fiber is made up of a core of refractive index 1.6 and a cladding of refractive index 1.5. What is the maximum angle that the light rays can make with the axis of the optical fiber so that light is totally reflected inside the optical fiber?
A) 10°
B) 15°
C) 20°
D) 70°
E) 90°
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For an object in front of a plane mirror, which of the following about its images is(are) true?
I) The image is real
II) The image is upright
III) The height of the image is twice the image of the object
A) I, II and III
B) I and II only
C) II only
D) I and III only
E) None
Solutions to Above Questions
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Light is an electromagnetic wave that can propagate in vacuum with a maximum speed of approximately 3×108 m/s.
Answer: C
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v = 50% c (c speed of light in vacuum)
Definition of refractive index n:
n = c / v
= c / 50% c = 2.0
Answer: D
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ic = arcsin(1.45/1.5) = 75°
Answer: E
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Light of any wavelength can be reflected and refracted. Light with a single wavelength cannot be dispersed.
Answer: A
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Snell's law
n1 sin (i) = n2 sin (r)
Use definition of refractive index: n = c / s (c speed of light in vacuum and s speed of light in the material)
(c/s1) sin (i) = (c / s2) sin (r)
sin (r) = (s2 / s1) sin (i)
s2 / s1 <1 leads to
sin(r) < sin (i)
r < i
The ray refract toward the normal.
Answer: B
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A convex lens is a converging lens. Rays parallel to the axis of a convex lens will emerge through the lens and all pass through the same point called the principal focus.
Answer: E
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Let do be the distance from lens to object, di distance from lens to the image and f be the focal length. Use the lens equation
1/do + 1/di = 1/f
1/50 + 1/di = 1 / 20
1/di = 1/20 - 1/50
di = 33 cm
So di which is the distance from the lens to the image is positive, therefore the image is real and inverted and on the opposite side of the object.
Answer: C
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Let do be the distance from lens to object, di distance from lens to the image and f be the focal length.
Let hi be the height of the image and ho be the height of the object.
First use the lens equation to find di.
1/do + 1/di = 1/f
1/25 + 1/di = 1/10
solve to find di = 17 cm
Magnification equation gives
hi / ho = - di / do
hi / 5 = - 17 / 25
hi = - 3.4 cm
Answer: D
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To have total internal reflection, the angle of incidence i must be larger than the critical angle ic.
i > ic
ic = arcsin(1.5/1.6) = 70 °
Let α be the angle made by the ray and the axis of the optical fiber. The relationship between α and i is:
α = 90° - i
i > ic
90° - α > 70°
α < 90° - 70°
α < 20 °
Answer: C
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The image of the object in front of a plane mirror is virtual, upright and of the same height as the object.
Answer: C